# Medial triangle Information

*https://en.wikipedia.org/wiki/Medial_triangle*

The **medial triangle** or **midpoint triangle** of a
triangle *ABC* is the triangle with
vertices at the
midpoints of the triangle's sides AB, AC and BC. It is the *n*=3 case of the
midpoint polygon of a
polygon with *n* sides. The medial triangle is not the same thing as the
median triangle, which is the triangle whose sides have the same lengths as the
medians of *ABC*.

Each side of the medial triangle is called a *midsegment* (or *midline*). In general, a midsegment of a triangle is a line segment which joins the midpoints of two sides of the triangle. It is parallel to the third side and has a length equal to half the length of the third side.

## Properties

The medial triangle can also be viewed as the image of triangle *ABC* transformed by a
homothety centered at the
centroid with ratio -1/2. Thus, the sides of the medial triangle are half and parallel to the corresponding sides of triangle ABC. Hence, the medial triangle is inversely
similar and shares the same centroid and
medians with triangle *ABC*. It also follows from this that the
perimeter of the medial triangle equals the
semiperimeter of triangle *ABC*, and that the
area is one quarter of the area of triangle *ABC*. Furthermore, the four triangles that the original triangle is subdivided into by the medial triangle are all mutually
congruent by
SSS, so their areas are equal and thus the area of each is 1/4 the area of the original triangle.^{
[1]}^{:p.177}

The
orthocenter of the medial triangle coincides with the
circumcenter of triangle *ABC*. This fact provides a tool for proving
collinearity of the circumcenter, centroid and orthocenter. The medial triangle is the
pedal triangle of the circumcenter. The
nine-point circle circumscribes the medial triangle, and so the nine-point center is the circumcenter of the medial triangle.

The
Nagel point of the medial triangle is the
incenter of its reference triangle.^{
[2]}^{:p.161,Thm.337}

A reference triangle's medial triangle is
congruent to the triangle whose vertices are the midpoints between the reference triangle's
orthocenter and its vertices.^{
[2]}^{:p.103,#206;p.108,#1}

The
incenter of a triangle lies in its medial triangle.^{
[3]}^{:p.233,Lemma 1}

A point in the interior of a triangle is the center of an
inellipse of the triangle if and only if the point lies in the interior of the medial triangle.^{
[4]}^{:p.139}

The medial triangle is the only
inscribed triangle for which none of the other three interior triangles has smaller area.^{
[5]}^{:p. 137}

## Coordinates

Let a = |BC|, b = |CA|, c = |AB| be the sidelengths of triangle ABC. Trilinear coordinates for the vertices of the medial triangle are given by

- X = 0 : 1/b : 1/c
- Y = 1/a : 0 : 1/c
- Z = 1/a : 1/b : 0

## Anticomplementary triangle

If *XYZ* is the medial triangle of *ABC*, then *ABC* is the **anticomplementary triangle** or **antimedial triangle** of *XYZ*. The anticomplementary triangle of *ABC* is formed by three lines parallel to the sides of *ABC*: the parallel to *AB* through *C*, the parallel to *AC* through *B*, and the parallel to *BC* through *A*.

Trilinear coordinates for the vertices of the anticomplementary triangle, X'Y'Z', are given by

- X' = −1/a : 1/b : 1/c
- Y' = 1/a : −1/b : 1/c
- Z' = 1/a : 1/b : −1/c

The name "anticomplementary triangle" corresponds to the fact that its vertices are the anticomplements of the vertices A, B, C of the reference triangle. The vertices of the medial triangle are the complements of A, B, C.

## See also

- Middle hedgehog, an analogous concept for more general convex sets

## References

**^**Posamentier, Alfred S., and Lehmann, Ingmar.*The Secrets of Triangles*, Prometheus Books, 2012.- ^
^{a}^{b}Altshiller-Court, Nathan.*College Geometry*. Dover Publications, 2007. **^**Franzsen, William N.. "The distance from the incenter to the Euler line",*Forum Geometricorum*11 (2011): 231–236.**^**Chakerian, G. D. "A Distorted View of Geometry." Ch. 7 in*Mathematical Plums*(R. Honsberger, editor). Washington, DC: Mathematical Association of America, 1979.**^**Torrejon, Ricardo M. "On an Erdos inscribed triangle inequality",*Forum Geometricorum*5, 2005, 137–141. http://forumgeom.fau.edu/FG2005volume5/FG200519index.html