1824 United States presidential election in Pennsylvania Article

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United States presidential election in Pennsylvania, 1824

←  1820 October 26 – December 2, 1824 1828 →
  Andrew Jackson.jpg JohnQAdams.jpg WilliamHCrawford.jpg
Nominee Andrew Jackson John Quincy Adams William H. Crawford
Party Democratic-Republican Democratic-Republican Democratic-Republican
Home state Tennessee Massachusetts Georgia
Running mate John C. Calhoun John C. Calhoun Nathaniel Macon
Electoral vote 28 0 0
Popular vote 35,929 5,436 4,182
Percentage 76.04% 11.50% 8.85%

President before election

James Monroe
Democratic-Republican

Elected President

John Quincy Adams
Democratic-Republican

The 1824 United States presidential election in Pennsylvania took place between October 26 and December 2, 1824, as part of the 1824 United States presidential election. Voters chose 28 representatives, or electors to the Electoral College, who voted for President and Vice President.

During this election, the Democratic-Republican Party was the only major national party, and four different candidates from this party sought the Presidency. Pennsylvania voted for Andrew Jackson over John Quincy Adams, William H. Crawford, and Henry Clay. Jackson won Pennsylvania by a wide margin of 64.54%.

Results

United States presidential election in Pennsylvania, 1824 [1]
Party Candidate Votes Percentage Electoral votes
Democratic-Republican Andrew Jackson 35,929 76.04% 28
Democratic-Republican John Quincy Adams 5,436 11.50% 0
Democratic-Republican William H. Crawford 4,182 8.85% 0
Democratic-Republican Henry Clay 1,705 3.61% 0
Totals 47,252 100.0% 28

References

  1. ^ "1824 Presidential General Election Results - Pennsylvania". U.S. Election Atlas. Retrieved 4 August 2012.