1996 United States presidential election in Hawaii Information
|Elections in Hawaii|
The 1996 United States presidential election in Hawaii took place on November 5, 1996, as part of the 1996 United States presidential election. Voters chose 4 representatives, or electors to the Electoral College, who voted for president and vice president.
Hawaii was won by President Bill Clinton ( D) over Senator Bob Dole ( R- KS), with Clinton winning 56.93% to 31.64% by a margin of 25.29%. Billionaire businessman Ross Perot ( Reform Party of the United States of America- TX) finished in third, with 7.6% of the popular vote. 
|1996 United States presidential election in Hawaii|
|Party||Candidate||Running mate||Votes||Percentage||Electoral votes|
|Democratic||Bill Clinton ( incumbent)||Al Gore||205,012||56.93%||4|
|Republican||Bob Dole||Jack Kemp||113,943||31.64%||0|
|Reform||Ross Perot||Patrick Choate||27,358||7.60%||0|
|Green||Ralph Nader||Winona LaDuke||10,386||2.88%||0|
|Libertarian||Harry Browne||Jo Jorgensen||2,493||0.69%||0|
|Natural Law||Dr. John Hagelin||Dr. V. Tompkins||570||0.16%||0|
|U.S. Taxpayers' Party||Howard Phillips||Herbert Titus||358||0.10%||0|
- Leip, David. "Dave Leip's Atlas of U.S. Presidential Elections". uselectionatlas.org. Retrieved 2018-06-14.